Math, asked by Anonymous, 7 months ago

Praveen has rupees 4662 in the from of 2 and 5, 10 rupees notes. if these notes are in the ratio of 3:5:8 the number of five rupees notes within him is​

Answers

Answered by JanviMalhan
1

Given :

  • Total rupees praveen has = Rs. 4662

  • In which there were 2 , 5 and 10 Rupees notes.

Assuming the notes are in ratio of 3:5:8

To find :

  • Total no. of Rs. 5 notes

Solution:

Let x to be included in the ratio then 3x , 5x and 8x

Let the no. of Rs 2 , Rs 5 and Rs 10 be 3x , 5x and 8x

Now According to question,

3x × 2 + 5x × 5 + 10x × 8 = Rs. 4662

= 6x + 25x + 80x = Rs.4662

= 111x = Rs. 4662

=> x = Rs. 4662/111

x = Rs. 42

Now finding the no. of all Rs. 2 , Rs. 5 and Rs.10 notes

No. of Rs.2 notes = 3× 42 = 126

No. of Rs.5 notes = 5 × 42 = 210

No. of Rs.10 notes = 8 × 42= 336

In question, it is asking the no. of only Rs. 5 notes

=210

Answered by MissHarshitaV
3

Answer:

Let the number of notes of Rs 2, Rs 5 and Rs 10 be 3x, 5x and 8x resp

Then, 3x * 2 + 5x * 5 + 10x * 8 = 4662

i.e. 111x = 4662

i.e. x = 42

Then, number of Rs 5 notes = 5 * 42

= 210

harshita here ❤️❤️❤️

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