Question

praveen travels 25m towards south then he turns left and travels 30mt then turns right and travels 15m. how far is he from the starting point ?

Answer 1

Answer:

50m

Step-by-step explanation:

First go through the diagram

Answer 2

Answer:

Here we will find distance between the starting point to where he stop his travel using the given data.

Distance of the starting point to end point $=50m$

Step-by-step explanation:

First he travels $25m$ towards south. Then he turns left and travels $30m$. Then he turns right and travels $15m$.

For the given question has the following diagram.

Here A is the starting point. D is the end point. We should find the distance of AD using Pythagoras theorem.

Pythagoras theorem:

        Pythagoras theorem is that, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

We apply this theorem for the given diagram.

Here hypotenuse = AD

           Two sides = AE and ED

From the diagram, AE = AB + BE

AB $=25m$.BE is parallel to CD. Already we know the CD value. So we can apply this value to BE. So that BE $=15m$

              AE = AB + BE

              AE $=25+15$

              AE $=40m$

Similarly, the second side ED is parallel to BC. Already we know the BC value. So we can apply this value to ED.

So that,  ED $=30m$.

Now we know the two sides values. So we can find the hypotenuse = AD

Using the Pythagoras theorem,

                   AD² = AE² + ED².

                   AD² $=40^{2}+30^{2}$

                   AD² $=1600+900$

                   AD² $=2500$

                   AD   $=\sqrt{2500}$

                   AD  $=\sqrt{50*50}$

                   AD  $=50m$.

Now he is $50m$ distance from the starting point.