Question

pravej spent 20% of his pocket money on transport and 60 rupees on his breakfast . If he spent 15% of the remaining money on his lunch and had 340 rupees left . What was his pocket money​

Answer 1

he spent on transport =20%

spent on breakfast =60/-

spent on lunch =15%

remaining amount=340

rs he spent on transport=20/100×340

=68

rs he spent on lunch=15/100×340

=51

total his pocket money=68+51+60+340

=₹519

Answer 2

Question :

Parvez spends 20% of his pocket money on transport in ₹60 on his breakfast. If he spent 15% of the remaining money on his lunch and had ₹340 left, what was his pocket money?

Solution :

$\sf{{Let \: his\: pocket\:}{money \: be \: ₹x}}.$

Then, money spent on transport = 20% of ₹x

$→ \frac{20}{100} \times ₹x = ₹( \frac{x}{5} )$

$\sf{{money \: spent\: on \: }{transportation \: and \: breakfast \: = ₹( \frac{x}{5} + 60)}}$

$\sf{{money \: }{left \: = ₹x - ( \frac{x}{5} + 60)}} = ₹( \frac{4}{5} )x - 60$

$\sf{{Now ,\: 15\%\: of \: \: ₹( \frac{4x}{5} - 60) \: }{was \:spent \: on \: lunch }}$

$\sf{{Then\: the\:amount \: }{left \: was \: 100\% - 15\% = 85\% \: of \: \: ₹( \frac{4x}{5} - 60)}}$

$\sf{{85\% \: of \: \: ₹( \frac{4x}{5} - 60) = ₹340 \: }{ \: \: \: or \: \frac{85}{100} \times ( \frac{4x}{5} - 6) = 340}}$

$\sf{{or \: \: \: \: \frac{4x}{5} - 60 = \: }{ \frac{340 \times 100}{85} \:}}$

$\sf{{or \: \: \: \: \frac{4x}{5} - 60 = \: }{400}}$

$\sf{{or \: \: \: \frac{4x}{5} \: = }{ \: 460}}$

$\sf{{or \: \: \: \: x = \: }{ \frac{5}{4} \times 460 = 575}}$

$\sf{{Hence, \: his\: }{pocket \: money \: was\:₹ 575.}}$

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$\sf{{Hope \: it\: }{helps \: you \: \: :) }}$