pravej spent 20% of his pocket money on transport and 60 rupees on his breakfast . If he spent 15% of the remaining money on his lunch and had 340 rupees left . What was his pocket money
Answers
Answer:
Rs. 575
Step-by-step explanation:
Given :-
Pravej spent 20% of his pocket money on transport and 60 rupees on his breakfast . If he spent 15% of the remaining money on his lunch and had 340 rupees left .
To find :-
What was his pocket money ?
Solution :-
Let the pocket money of Pravej be Rs. X
Money spent on transport = 20% of the pocket money
=> 20% of Rs. X
=> 20% × X
=> (20/100)×X
=> (1/5)×X
=> X/5
Money spent on transport = Rs. X/5
Money spent on his breakfast = Rs. 60
Total money spent on transport and his breakfast = Rs. (X/5)+60
= Rs. (X+300)/5
Remaining money = Total money - Expenditure
=> X - [(X+300)/5]
=> (5X-(X+300))/5
=> (5X-X-300)/5
=> (4X-300)/5
Remaining money = Rs. (4X-300)/5
Money spent on his lunch = 15% of the remaining money.
=> 15% of Rs. (4X-300)/5
=> 15% × (4X-300)/5
=> (15/100) × (4X-300)/5
=> (3/20) × (4X-300)/5
=> (3×(4X-300))/(20×5)
=> (12X-900)/100
=> 4(3X-225)/100
=> (3X-225)/25
Money spent on his lunch = Rs. (3X-225)/25
Remaining Money =
=> Rs. (4X-300)/5 - Rs. (3X-225)/25
=> [ 5(4X-300) - (3X-225)]/25
=> [(20X-1500)-(3X-225)]/25
=> (20X-1500-3X+225)/25
=> (17X-1275)/25
Total remaining money = Rs. (17X-1275)/25---(1)
According to the given problem
Remaining money he had = Rs. 340---(2)
both (1) &(2) are same
=> (17X-1275)/25 = 340
=> 17X -1275 = 340×25
=> 17X -1275 = 8500
=> 17X = 8500 + 1275
=> 17X = 9775
=> X = 9775/17
=> X = 575
Therefore, X = Rs. 575
Answer:-
The pocket money of Pravej is Rs. 575
Check :-
The pocket money of Pravej is Rs. 575
Money spent on transport = 20%
=> (20/100)×575
=> (20×575)/100
=> 11500/100
=>Rs. 115
Money spent on his breakfast = Rs. 60
Total spent money = 115+60 = Rs. 175
Remaining money = 575-175 = Rs. 400
Money spent his lunch = 15% of remaining
=> 15% of 400
=> (15/100)×400
=> (15×400)/100
=> 15×4
=> 60
Remaining money = 400-60 = Rs. 340
Verified the given relations in the given problem.
Answer:
let his pocket money be x
Step-by-step explanation:
transport = 20/100x
breakfast = 60
money left = x-(20/100x+60)
lunch = 15/100[x-(20/100x +60)]
money left =340
x= 20/100x + 60 + 15/100[x-(20/100x + 60)] +340
x = 1/5x + 3/20x - 3/100x -9 +400
x = 32/100x + 391
x - 32/100x = 391
68x = 38100
x = 575
his pocket money was Rs 575
verify
transport = 20% of 575 = 115
bf = 6
total spent = 115 + 60 = 175
rem = 575 - 175 = 400
lunch 15% of 400 = 60
money left = 340
115 +60 + 60 + 340 = 575