Predict the block, period and group to which Iridium (atomic number 77) belongs and justify your answer
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Hello dear,
● Answers with explanations-
Let's first write electronic configuration of iridium (Z=77).
- Condense E.C. = [Xe] 4f14 5d7 6s2
a) Block-
Iridium receives last eleectron in d-orbit
Hence, block = d
b) Period -
Principle quantum number of last shell is 6.
Hence, period = 6
c) Group -
No of electrons in ultimate and penultimate shell is 7+2=9.
Hence, group = 9
Hope this helps you..
● Answers with explanations-
Let's first write electronic configuration of iridium (Z=77).
- Condense E.C. = [Xe] 4f14 5d7 6s2
a) Block-
Iridium receives last eleectron in d-orbit
Hence, block = d
b) Period -
Principle quantum number of last shell is 6.
Hence, period = 6
c) Group -
No of electrons in ultimate and penultimate shell is 7+2=9.
Hence, group = 9
Hope this helps you..
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