Question

predict the change in entropy in following reaction
H2 converting Into 2H??

Answer 1

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BaSO4<............>Ba+..+..SO4-
C........................0...........0.......(intially)
C-s.....................s..............s........(at equilibrium)
where s is the solubility(mol/litre) and C is the initial concentration(mol/litre)
Hence, solubility product Ksp=s2
1.5*10-10=s2
hence, s=~1.2*10-5mol/litre



BaSO4 ionises to give –
BaSO4 Ba2+ + SO42--
Suppose solubility of BaSO4 is s mol/l.It would give s mol/l of Ba2+ ions and s mol/l of SO42- ions on dissociation.
Now, solubility product for BaSO4 is expressed as-
Ksp = [Ba2+] [SO42--] = [s]* [s] = s2
thus,
s2 = 1.5*10--10
or,
s =1.5*10-10
s = 1.225 * 10--5
thus, solubility of BaSO4 will be 1.225 * 10 --5mol/l.

Answer 2

First of all let me tell you what is entropy -

In general, Entropy is a measure of randomness

So in the above equation H2 spilts into 2 H atoms therefore as no. of gaseous atoms increases randomness increases and hence more will be the entropy.

So at last we would conculde that the entropy increases when H2 breaks down into 2H.