Question

Predict the feasibility of a reaction when

(i) both delta H and delta S increases.

(ii)both delta H and delta S decreases.

(iii)delta H increases but delta S decreases.

(iv)delta H decreases but delta S increases.

Answer 1

Answer: Option (iv) is the correct answer.

Explanation:

The relation between delta G, delta H, and delta S is as follows.

           $\Delta G = \Delta H - T\Delta S$

where,       $\Delta G$ = Gibb's free energy

                  $\Delta H$ = enthalpy

                  T = temperature

                  $\Delta S$ = entropy

A reaction will be feasible only when degree of randomness, that is, delta S increases and more heat will be released which means enthalpy is decreasing. Therefore, value of delta G will be as follows.

                     $\Delta G$ = $\Delta H - T\Delta S$

                                     = -ve - T(+ve)

                                     = -ve - ve

                                     = -ve

Therefore, value of delta G will also be negative.

Thus, we can conclude that delta S should be positive and delta H should be negative for the feasibility of a reaction and the reaction will be spontaneous.

Answer 2

Explanation:

THE ANSWER IS IN ABOVE ATTACHED PICTURE.

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