Predict the nature of bond.
Orbits Internuclear axis Bond
s + s any axis .................
s + px x-axis .................
s + py y-axis .................
s + px z-axis .................
px + px x-axis .................
py + py y-axis .................
pz + pz z-axis .................
px + px y or z-axis .................
py + py x or z-axis .................
pz + pz x or y-axis .................
plzzzzz give me full solution of this.
Answers
Answered by
192
this question is based on valance bond theory .
1) s + s both are sphereical shape so, no directional bond form , it means sigma bond exist here .
s + px , s + py and s + pz all have unidirectional bond . here also form sigma bond .
px + px , py + py , and pz + pz all overlap in x -axis , y -axis , z -axis respectively. so, here head on overlapping exist .
so, sigma bond will bare form by this
px + px in y or z -axis side-wise overlapping so, pi-bond will be form
py + py in x or z -axis also form pi -bond
pz + pz in x or y -axis also form pi-bond
1) s + s both are sphereical shape so, no directional bond form , it means sigma bond exist here .
s + px , s + py and s + pz all have unidirectional bond . here also form sigma bond .
px + px , py + py , and pz + pz all overlap in x -axis , y -axis , z -axis respectively. so, here head on overlapping exist .
so, sigma bond will bare form by this
px + px in y or z -axis side-wise overlapping so, pi-bond will be form
py + py in x or z -axis also form pi -bond
pz + pz in x or y -axis also form pi-bond
ashermitul5:
plz explain your answer in diagrammatic way.
Answered by
11
the answer is given in the image
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