predict the numbers of unpaired electron in square planner [Pt(CN)4]2- ion?
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hey!!
here is your answer!!!
as e.c of pt is 5d8 7s2
but in this compound it's oxidation state is+2so its final e.c is 5d8
as CN IS A STRONG LIGAND SO IT EXCITE THE ELECTRON AND SHOW DSP2 HYBRIDISATION WITH DIAMAGNETIC CHARACTER
HENCE NO UNPAIRED ELECTRON
HOPE HELP U!!
MARK ME!!!
here is your answer!!!
as e.c of pt is 5d8 7s2
but in this compound it's oxidation state is+2so its final e.c is 5d8
as CN IS A STRONG LIGAND SO IT EXCITE THE ELECTRON AND SHOW DSP2 HYBRIDISATION WITH DIAMAGNETIC CHARACTER
HENCE NO UNPAIRED ELECTRON
HOPE HELP U!!
MARK ME!!!
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