Predict the output of the following python program:
num,sum=10,0
for i in range(1,num+2,2):
if i % 3 == 0:
continue sum =
sum + i
print(sum)
Answers
Output:
1
6
13
24
Explanation:
num, sum = 10, 0
for i in range(1, num+2, 2):
if i%3==0:
continue
sum=sum+1
print(sum)
Here, num is initiated with 10 while sum with 0.
The looping range starts from 1 and ends with num+2 i.e., 10+2=12 [12 is excluded], with the gap of 2.
i.e., iteration goes on as [1, 3, 5, 7, 9, 11]
Now, the iterable value that is exactly divisible by 3 leaving remainder 0 will pa-ss the control to the next iteration directly, leaving the execution on the next statements due to the triggering of the continue statement.
1%3 is not equal to 0. So, sum = 0 + 1 => sum=1 and 1 is printed.
3%3==0. So, the loop directly goes for the next iteration, the sum remains 1.
5%3 is not equal to 0. So, sum = 1 + 5 => sum=6 and 6 is printed.
7%3 is not equal to 0. So, sum = 6 + 7 => sum=13 and 13 is printed.
9%3==0. So, the loop directly goes for the next iteration, the sum remains 13.
5%3 is not equal to 0. So, sum = 13 + 11 => sum=24 and 24 is printed.
Therefore the output is:
1
6
13
24
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