Question

Predict the output of the following python program: r = lambda q: q * 2 s = lambda q: q * 3 x = 2 x = r(x) x = s(x) x = r(x) print x *

Answer 1

Explanation:

r and s are lambda functions or anonymous functions and q is the argument to both of the functions. In first step we have initialized x to 2. In second step we have passed x as argument to the lambda function r, this will return x*2 which is stored in x. That is, x = 4 now. Similarly in third step we have passed x to lambda function s, So x = 4*3. i.e, x = 12 now. Again in the last step, x is multiplied by 2 by passing it to function r. Therefore, x = 24.

Answer 2

The output of the given Python program would be 72.

Here's how the output is obtained:

• First, we define two lambda functions r and s, which multiply their input by 2 and 3 respectively.
• We then assign the value 2 to the variable x.
• Next, we call the lambda function r with x as the argument. This sets the value of x to 4 (2 * 2).
• We then call the lambda function s with x as the argument. This sets the value of x to 12 (4 * 3).
• Finally, we call the lambda function r with x as the argument. This sets the value of x to 24 (12 * 2).
• We then print the value of x multiplied by an implicit 1, which gives us the final output of 72 (24 * 1).

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