Predict the oxidation state of metal ion in the foll compounds
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MnCl2
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Answer:
Consider the oxidation state of Mn as x.
The charges on Cl,O,H,K are −1,−2,+1,+1 respectively. Therefore, the oxidation states of Mn in its given compounds can be calculated as follows:
MnCl
2
→ x+(−2)=0 ⇒ x=+2
Mn(OH)
3
→x+(−3)=0⇒x=+3
MnO
2
→x+(−4)=0⇒x=+4
KMnO
4
→+1+x+(−8)=0⇒x=+7
Hence, option B is the correct answer of this question.
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