Question

predict the products of electrolysis of an aqueous solution of CuCl2 with Pt electrodes​

Answer 1

Answer:

Remember

All ions are in aqueous state

(i)

Reaction in solution

AgNO3               ↔     Ag+    +        NO3–

H2O             ↔     H+       +        OH–

Reaction at cathode

Ag+   +          e-→      Ag

Reaction at anode

Ag(s)  +        NO3– →      AgNO3(aq)   +       e-

Hence Ag will deposit at cathode and dissolve at anode

(ii)

Reaction in solution

AgNO3               ↔     Ag+    +        NO3–

H2O             ↔     H+       +        OH–

Reaction at cathode

Ag+   +          e-→      Ag

Reaction at anode

Due to platinum electrode self of ionization of water will take place  

H2O   →     2H+    +        1/2O2(g)   +  2e-

Hence Ag will deposit at cathode and O2 gas will generate at anode

(iii)

Reaction in solution

H2SO4                          ↔     2H+  +        SO42–

H2O             ↔     H+       +        OH–

Reaction at cathode

H+      +          e-→      ½ H2

Reaction at anode

Due to platinum electrode self of ionization of water will take place  

H2O   →     2H+    +        1/2O2(g)   +  2e-

Hence H2 gas will generate at cathode and O2 gas will generate at anode

(iv)

Reaction in solution

CuCl2(s)      ↔     Cu2+            +        2Cl–    

H2O             ↔     H+       +        OH–

Reaction at cathode

Cu2+    +        2e-→      Cu(S)

Reaction at anode

2Cl–             →      Cl2     +  2e-

Explanation: