Question

predict the sign of delta S for reaction N2+3H2-2NH3

Answer 1

Negative.

Because no. Of gaseous molecules are lower at product side therefore there is lesser degree of disorderness.

Answer 2

The sign of $\Delta S$ for reaction $N_2+3H_2\rightarrow 2NH_3$ is negative

Explanation:

Entropy is the measure of randomness or disorder of a system. If a system moves from  an ordered arrangement to a disordered arrangement, the entropy is said to decrease and vice versa.

For the reaction:

$N_2(g)+3H_2(g)\rightarrow 2NH_3(g)$

In this reaction 4 moles of gaseous reactants are converting to 2 moles of gaseous products. The randomness will decrease and hence entropy will also decrease. Thus $\Delta S$ is negative.

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