Chemistry, asked by abhishek93506, 10 months ago

Predict the state of the solute in the following situations :
(a) Experimentally determined molar mass is more than the true value.
(b) 'i' value is 0.4 .

Answers

Answered by Draxillus
6

Answer:

(a) Molecules in associated form

(b) Molecules in associated form

Explanation:

we know,

i =

 \frac{normal \: molar \: mass}{abnormal \: molar \: mass}

we have, abnormal molar mass > normal molar mass.

It can only be possible if molecules are in associated state.

(B) since, i < 1 , again, it is association .

Regards

Kshitij Ampearl

Answered by Jasleen0599
4

The state of the solute in both the given situations is associated form of  molecules.

(a) We know that i = normal molar mass/ abnormal molar mass

But it is given that experimentally determined molar mass is more than the true value.

⇒ i < 1

(b) It is already given that i = 0.4

- We know that i < 1 for association.

- Since i < 1 in both the cases, the molecules of the solute are in associated form in both the cases.

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