Predict whether F2 and Na react with one another. give reason E°F2/F- = +2.87 V, E°Na+/Na=-2.71V
Answers
Given:
E°F2/F- = +2.87 V, E°Na+/Na = -2.71 V
To find:
Predict whether F2 and Na react with one another.
Solution:
E₀ cell = E₀ reduction - E₀ oxidization
From given, we have,
E₀ cell = 2.87 V - (-2.71 V) = 5.58 V
Na → Na+ + e- (oxidation)
F- + 2e- → F2 (reduction)
As the emf of the cell is positive (E₀ cell = 5.58 V),
the reaction between Na and F is spontaneous and will react with each other.
Answer:
Yes they would react with each other
Explanation:
In a electrochemical cell, a chemical reaction of oxidation and reduction takes place. One cell is oxidised while the other gets reduction
Now we are given that
E of F is 2.87 while E of Na is -2.71
Overall potential difference between the cells
EMF = 2.87 V - (-2.71 V)
= 5.58 V
Since the potential difference is sufficient so F2 and Na would react with each other