Preeti is painting the wall and ceiling of a hall whose dimensions are 18m ×15m×5m . From each can of paint 120m^2 of area is painted. How many cans of paint she need to paint the hall
Answers
Answered by
45
area to be painted = LSA + ceiling area
= 2(bh+hl) + lb
= 2(18*5+15*5) + 18*15
= 2(90+75) + 270
= 2*165 + 270
= 330 + 270
= 600 m²
no. of cans = area / amount per can
= 600/120
= 5
therefore she'll need 5 cans of paint
= 2(bh+hl) + lb
= 2(18*5+15*5) + 18*15
= 2(90+75) + 270
= 2*165 + 270
= 330 + 270
= 600 m²
no. of cans = area / amount per can
= 600/120
= 5
therefore she'll need 5 cans of paint
Sahilkumar123:
Please tall me what is meaning by LSA that you wrote in this question
LSA means Lateral Surface Are
*Area
it is the total surface area minus the top and bottom areas
so LSA of a room will be the area of its walls (not including ceiling and floor)
did you understand
if you did please mark as brainliest
thanks
Answered by
11
dimensions:-
l = 18m
b = 15m
h = 5m
TSA= 2(lb+ bh+ hl)
= 2(270+75+90)
= 2* 435
= 870m^2
cans needed = 870/120
= 7.25 cans
l = 18m
b = 15m
h = 5m
TSA= 2(lb+ bh+ hl)
= 2(270+75+90)
= 2* 435
= 870m^2
cans needed = 870/120
= 7.25 cans
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