Preparation of 0.1m standard solution of oxalic acid
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Theory
The molecular mass of oxalic acid is 126. In order to prepare M/10oxalic acid solution, 12.6 g of oxalic acid should be dissolved per litre of solution. Alternatively, 12.6 /4 = 3.15 g of oxalic acid crystals should be dissolved in water and the solution be made exactly 250 ml.
Apparatus
Weight box, chemical balance, watch glass, 250 ml beaker, glass rod, 250 ml measuring flask, wash bottle.
Procedure
1. Take a watch glass, wash it with distilled water and then dry it.
2. Weigh the clean and dried watch glass accurately and record its weight in the note-book.
3. Weigh 2.650 g sodium carbonate on the watch glass accurately and record this weight in the note-book.
4. Transfer gently and carefully sodium carbonate from the watch glass into a clean and dry measuring flask using a funnel. Wash the watch glass with distilled water with the help of a wash bottle to transfer the particles sticking to it into funnel [Fig. 8.7(a)]. The volume of distilled water for this purpose should not be more than 50 ml.
5. Wash funnel several times with distilled water by using a wash bottle to transfer the sticking particles into the measuring particles into the measuring flask. While washing the funnel, add water in small amounts. The volume of distilled water used for this purpose should not be more than 50 mL.
6. Finally wash the funnel thoroughly with distilled water with the help of a wash bottle to transfer the solution sticking to the funnel into the measuring flask [Fig. 8.7(6)].
7. Swirl the measuring flask till solid sodium carbonate dissolves.
8. Add enough distilled water to the measuring flask carefully upto just below the etched mark on it, with the help of wash bottle.
9. Add the last few mL of distilled water dropurse until the lower level of the meniscus just touches the mark on the measuring flask [Fig. 8.7(c)].
10. Stopper the measuring flask and shake gently to make the solution uniform throughout. Label it as M/10 oxalic acid solution.
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The molecular mass of oxalic acid is 126. In order to prepare M/10oxalic acid solution, 12.6 g of oxalic acid should be dissolved per litre of solution. Alternatively, 12.6 /4 = 3.15 g of oxalic acid crystals should be dissolved in water and the solution be made exactly 250 ml.
Apparatus
Weight box, chemical balance, watch glass, 250 ml beaker, glass rod, 250 ml measuring flask, wash bottle.
Procedure
1. Take a watch glass, wash it with distilled water and then dry it.
2. Weigh the clean and dried watch glass accurately and record its weight in the note-book.
3. Weigh 2.650 g sodium carbonate on the watch glass accurately and record this weight in the note-book.
4. Transfer gently and carefully sodium carbonate from the watch glass into a clean and dry measuring flask using a funnel. Wash the watch glass with distilled water with the help of a wash bottle to transfer the particles sticking to it into funnel [Fig. 8.7(a)]. The volume of distilled water for this purpose should not be more than 50 ml.
5. Wash funnel several times with distilled water by using a wash bottle to transfer the sticking particles into the measuring particles into the measuring flask. While washing the funnel, add water in small amounts. The volume of distilled water used for this purpose should not be more than 50 mL.
6. Finally wash the funnel thoroughly with distilled water with the help of a wash bottle to transfer the solution sticking to the funnel into the measuring flask [Fig. 8.7(6)].
7. Swirl the measuring flask till solid sodium carbonate dissolves.
8. Add enough distilled water to the measuring flask carefully upto just below the etched mark on it, with the help of wash bottle.
9. Add the last few mL of distilled water dropurse until the lower level of the meniscus just touches the mark on the measuring flask [Fig. 8.7(c)].
10. Stopper the measuring flask and shake gently to make the solution uniform throughout. Label it as M/10 oxalic acid solution.
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Concept:
Molarity can be defined as the number of moles of solute per liter of solution.
Molarity = Moles of solute / Litres of solution
Moles = Weight/ Molecular weight
Given:
0.1 M of the standard solution of the oxalic acid.
Find:
The weight and volume required to make 0.1 M of the standard solution of oxalic acid.
Solution:
0.1M of the standard solution of Oxalic acid contains solvent as water as 100mL.
The molecular weight of oxalic acid is 126g/mol.
V = 100 mL
Molarity = (Weight/ Molecular weight) / Litres of solution
0.1 = (Weight/ 126) / (100/1000)
0.1 = (Weight/ 126) / (0.1)
Weight = 126 × 0.01 = 1.26 grams
Hence, when 1.26 grams of oxalic acid is dissolved in 100 ml of water 0.1 M of the standard solution of the oxalic acid can be prepared.
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