Chemistry, asked by zarnish6, 1 month ago

Preparation of
2-Bromo propone
from 1 - Bromo propone

plz explain the equation as well​

Answers

Answered by rashigondane25
0

dehydrohalogenation of 2-bromopropane gives propene and then this reaction is followed by hydrohalogenation of alkene by antimarkownikoff's rule

Explanation:

ch3—ch—ch3 +KOH(alc) –––› ch3–ch=ch2

| (potassium hydroxide) (propene)

Br

(1-bromopropane)

ch3–ch=ch2 +HBr ––––––› ch3–ch2–ch2–Br

peroxide

(propene) (hydrogen bromide). (1-bromopropane)

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