Preparation of
2-Bromo propone
from 1 - Bromo propone
plz explain the equation as well
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dehydrohalogenation of 2-bromopropane gives propene and then this reaction is followed by hydrohalogenation of alkene by antimarkownikoff's rule
Explanation:
ch3—ch—ch3 +KOH(alc) –––› ch3–ch=ch2
| (potassium hydroxide) (propene)
Br
(1-bromopropane)
ch3–ch=ch2 +HBr ––––––› ch3–ch2–ch2–Br
peroxide
(propene) (hydrogen bromide). (1-bromopropane)
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