Chemistry, asked by pklusifer52, 1 year ago

Preparation of 2 hydroxy 1 naptahdehyde by reimen tiemen reaction

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Answered by pooja6420
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2-Hydroxy-1-naphthaldehyde has been prepared from β-naphthol, zinc chloride, and hydrogen cyanide;1 from β-naphthol, zinc cyanide, and anhydrous hydrogen chloride;2from β-naphthol, chloroform, and sodium hydroxide(Reimer-Tiemann reaction);3,4 from β-naphthol and hexamethylene tetramine in glycerin-boric acid, followed by hydrolysis;5 and by hydrolysis of 2-hydroxynaphthaldehyde anil,6 prepared in turn from 2-hydroxydithionaphthoic acid.
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