Chemistry, asked by pinkimonkey9, 10 months ago

preparation of mohrs salt​

Answers

Answered by shraddhasingh3031
1

Answer:

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Explanation:

Mohr's salt is prepared by dissolving an equimolar mixture of hydrated ferrous sulfate and ammonium sulfate in water containing a little sulfuric acid, and then subjecting the resulting solution to crystallization. Ferrous ammonium sulfate forms light green crystals.

•Solubility in water: 269 g/L (hexahydrate)

•Chemical formula: Fe(SO4)(NH4)2(SO4) (anhydrous); Fe(SO4)(NH4)2(SO4)·6H2O ...

•Molar mass: 284.05 g mol−1 (anhydrous); 392.13 g mol−1 (hexahydrous

Answered by trishasaha111
0

Answer:

Mohr's salt is prepared by dissolving an equimolar mixture of hydrated ferrous sulfate and ammonium sulfate in water containing a little sulfuric acid, and then subjecting the resulting solution to crystallization. Ferrous ammonium sulfate forms light green crystals.

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