prepare 200 ml (m/20) aq solution of na2co3 (with explaination please)
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Answer:Molarity = no. Of moles of solute/ litre of solution
Since 100ml = 0.1 L
Therefore , 0.5 = no. of moles of solute/ 0.1
Hence,No. of moles of solute = 0.05 moles.
But , no. Of moles = mass of substance/ molecular mass of substance
So , 0.05 = mass of substance/ 106 = 5.3
Hence , mass or amount of sodium carbonate in litre of solution is 5.3
Calculation of molecular weight of sodium carbonate , = 23 *2 + 12*1 + 16 *3= 106.
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