Chemistry, asked by katalaashish, 3 months ago

Prepare 250 ml of 0.05 m(M/20) Oxalic acid solution from crystalline oxalic acid.

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Answered by ashauthiras

Answer:

Molecular formula of solid crystalline oxalic acid: H2C2O4, 2H2O. Its Molecular Wt. 126. Hence, to prepare 250 ml M/20 oxalic acid solution 126*250/(20*1000) = 1.575 gram of oxalic acid is to be dissolved in water in a 250 ml volumetric flask.

Explanation:

Answered by s7b1576simran2436

Answer:

Prepare 250 ml of 0.05 m(M/20) Oxalic acid solution from crystalline oxalic acid.

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Prepare 250 ml of 0.05 m(M/20) Oxalic acid solution from crystalline oxalic acid.​

Answers

Prepare 250 ml of 0.05 m(M/20) Oxalic acid solution from crystalline oxalic acid.