Question

Prepare 250 ml of M/20 solution of oxalic acid.
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Answer 1

In order to prepare 250 ml of M/20 solution of oxalic acid, we need 1.575 grams of oxalic acid.

Preparation of m/20 solution of oxalic acid

Theory:

The organic formula for oxalic acid= $(COOH)_{2} .2H_{2} O$

The molecular mass of oxalic acid= 126 grams

Calculation:

The amount of oxalic acid needed to make 1000 ml of solution = 126 grams

Now, the quantity of  $(COOH)_{2} .2H_{2} O$ needed to produce a 250 ml of M/20 solution =126× 250  ÷ 1000 ×20

= 31500÷1000×20

= 1.575 grams

Result:

In order to prepare 250 ml of M/20 solution of oxalic acid, we need 1.575 grams of oxalic acid.

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Answer 2

In order to prepare 250 ml of M/20 solution of oxalic acid, we need 1.575 grams of oxalic acid.

Preparation of an oxalic acid m/20 solution.

Theory:

oxalic acid's organic formula is $(COOH)_{2} 2H_{2}O$ .

Oxalic acid has a molecular mass of 126 grams.

Calculation:

To make 1000 mL of solution, you'll need 126 grams of oxalic acid.

The amount of $(COOH)_{2} 2H_{2}O$ required to make a 250 ml M/20 solution is now known.

= 126× 250  ÷ 1000 ×20

= 31500÷1000×20

= 1.575 grams

Hence, 1.575 grams of oxalic acid are required to make 250 mL of M/20 oxalic acid solution.

Learn more about oxalic acid here,

https://brainly.in/question/38979394?msp_poc_exp=4

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