Question

prepare a continuous frequency distribution table from the following data:-

mid value 5 15 25 35 45
frequency 4 8 13 12 6

Answer 1

The lower limit for every class is the smallest value in that class.

The lower boundary of each class is calculated by subtracting half of the gap value 12=0.5 1 2 = 0.5 from the class lower limit.

Simplify the lower and upper boundaries columns.

Add the lower and upper class boundaries columns to the original table.
PLEASE MARK MY ANSWER AS A BRAINLIEST.

Answer 2

The solution is in the image↑↑