Question

Prepare a frequency. distribution
table:
34.29.4 3.31.26 36.44.49.25,
26, 33, 39.42,4221,52,55
And then draw a graph​

Answer 1

Step-by-step explanation:

Given the total frequency is 1000 and the median is 412.50 find the missing frequencies class interval 300-325, 325-350,350-375,375-400,400-425,425-450,450-475,475-500 frequency 5,17,80,x,326,y,88,9

So calculate cf or cumulative frequency = 5 22 102 102 + x 428 + x 428 + x + y 516 + x + y 525 + x + y

Total frequency is 1000 = N

We know that median = 412.50, l = lower limit = 400 and h = 25(size)

M = l + [N/2 - cf / f] h

412.5 = 400 + [1000/2 - (102 + x)] 25 / 326

412.5 - 400 = (500 - 102 - x)/326 x 25

12.50 =(398-x)/326×25

12.50×326=( 398-x)×25

4075= (398-x)×25

4075/25 = (398-x)

163 =398-x

X=398-163=235

525 + x + y = 1000

525 + 235 + y = 1000

y = 240

So x = 235 and y = 240