Math, asked by pratikpatidar, 1 year ago

prepare a quadratic equation whose roots are 1÷2;1÷2

Answers

Answered by sr0575469p5wguj
0

two \: roots \: \: are \:  (\frac{1}{2}) and \: ( \frac{1}{2} ) \\ the \: formula \: for \: quadratic \: eqn \: is \: k {x}^{2}  -  ( \alpha +   \beta ) \:  + ( \alpha  \beta ) \\ ie \:  {x}^{2}  -  \frac{1}{2}  +  \frac{1}{2} \\  {2x}^{2}  - 1 + 1 \\ is \: the \: required \: eqn
Answered by Shalmali040203
0

Answer:

The quadratic polynomial is  4x² - 4x + 1

Step-by-step explanation:

Given ::- roots are 1/2 and 1/2

Solution::-

Let roots be α and β

So, α + β = 1/2 + 1/2

= 1+1 /2

= 2/2

= 1

αβ = 1/2 × 1/2

= 1/4

The general formula for quadratic equation is ::-

x² - (α + β)x + (αβ)

= x² - (1)x + (1/4)

= x² - x + 1/4

Multiplying the equation with 4

= 4x² - 4x + 1

This is the required quadratic polynomial


HOPE IT HELPS YOU!!

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