Question

prepare a standard solution of common salt in 100cc of water​

Answer 1

Explanation:

Given,

Molarity of HCl=0.1M

Volume of HCl=100cc=100ml

Distilled water volume=900cc=900ml

Now, the new concentration is calculated by

M

1

V

1

=M

2

V

2

Here V

2

=100ml+900ml=Final Volume

M

2

=Final concentration

⇒M

2

=

V

2

M

1

V

1

=

1000

0.1×100

=0.01M

Now, if 100ml of final solution is taken, the molarity will remain same

∴ Molarity of 100ml of final solution=0.01M

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