Question

prepare a truth table for following expression
abcd+ab(c+d)+a(b+c)'d+a'b c'd(a+b+c)d'
​

Answer 1

Answer:

abcd+ab(c+d)+a(b+c)'d+a'b c'd(a+b+c)d'

As dd'=0

So, a'b c'd(a+b+c)d' = 0

Now,

abcd+ab(c+d)

abcd + abc + abd