Prepare algorithm for 1. for i=o and 1=4,
1.1. get the num [I]
1.2. sum= sum+ num[I]
2. Average = sum/5 3. Print Sum
4. Print Average
Answers
Explanation:
How do I write an algorithm that calculate the sum and average of all even numbers between 1 and 50?
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12 Answers

Akhilesh Kumar, MCA Computer Science, Galgotias University (2019)
Answered Apr 27, 2018
Algorithm : →
Step 1 : Start
Step 2 : sum = 0, i = 1, average, count = 0
Step 3 : if i / 2 == 0 then go to step 4, else go to on step 5
Step 4 : sum = sum + i, count = count + 1
Step 5 : i = i + 1
Step 6 : if i <= 50 then go to on step 3, else go to on step 7
Step 7 : Display “sum”
Step 8 : average = sum/count
Step 9 : Display “average”
Step 10 : Stop
—————————————————————————————————————
Alternative : →
Step 1 : Start
Step 2 : sum = 0, i = 0, average, count = 0
Step 3 : i = i + 2
Step 4 : sum = sum + i, count = count + 1
Step 5 : if i <= 50 then go to on step 3, else go to on step 6
Step 6 : Display “sum”
Step 7 : average =sum/count
Step 8 : Display “average”
Step 9 : Stop
14.2k views · View 7 Upvoters
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Kalani Tharaka, Software Engineer (R&D) (2020-present)
Answered Mar 15, 2020
n=1
sum = 0
Check whether the n is even
If n is even, sum = sum + n
n = n + 1
If n < 50 , return to step 3
Stop
495 views · View 1 Upvoter · Answer requested by Pratik Patil
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Rahul Dey, lived in Kolkata, West Bengal, India
Answered Apr 27, 2018 · Author has 459 answers and 320.6k answer views
There are 25 even numbers between 1 and 50 (both inclusive). The first even number is 2 and the last one is 50. Using the sum of an arithmetic series formula this problem can be solved very easily.
sum of ap = n/2(a + l) where n is the number of terms in the AP and a and l are the first and last term.
So the code would look like this in c/c++ and with little modificaiton in java as well.
int main() {
int n = 25, a = 2, l = 50;
int sum = (n * (a + l))/2;
int average = sum/n;
//printing code goes here
return 0;
}
2.4k views · View 2 Upvoters

Neil Gupta, In Calculus AB
Answered Apr 28, 2018 · Author has 869 answers and 694.4k answer views
sum = 0
n = 0
i = 2
while i < 50:
sum += i
n += 1
i += 2
print 'sum: {}'.format(sum)
print 'avg: {}'.format(float(sum) / n)
5k views
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Lukas Schmidinger, I have passed some math courses in university.
Answered Apr 27, 2018 · Author has 14.7k answers and 3.2m answer views
The sum of all even numbers from 11 to nn is
2×∑k=1