Question

Prepare m/40 solution of oxalic acid. With the help, determine the molarity and strength of the given solution kmno4

Answer 1

Answer:

Determining the molarity of the given KMnO4 solution -

Take known volume of KMnO4 solution and titrate it against oxalic acid of M/40 concentration.

Balanced molecular eqn is -

2KMnO4 + 2H2SO4 + 5(COOH)2--> K2SO4 + 2MMnSO4 + 18H2O

+ 10CO2

(a) Molarity-

M(KMnO4)*V(KMnO4) / M(oxalic acid) = 2/5

M(KMnO4) = V(oxalic acid) / 100V(KMnO4)

(b) Strength -

Strength(KMnO4) = M(KMnO4)* Molecular mass

Explanation:

Answer 2

Molarity and strength determination of the solution $KMnO4$This chemical reaction is a redox reaction

Explanation:

• AIM :- Determination of the strength of potassium permanganate with the help of $M/40$ oxalic acid
• Solutions required :- Oxalic Acid, Potassium Permanganate,
• Reaction against chemical analysis of oxalic acid
• The titrant is in the chemical analysis and the oxalic acid is the analyte.
• The reaction between potassium permanganate and oxalic acid occurs in acidic medium and acidity is produced by dilute. Here the pointer itself works.
• Take 10 ml solution of oxalic acid in a flask.
• Add 5ml 1.0M sulfuric acid to it. First heat the solution to 50-60 ℃ with a solution of potassium permanganate.
• Initially pink color of potassium permanganate reacts with oxalic acid
• The process in which a chemical change takes place is called a chemical reaction.