prepared a solution of potassium chloride by mixing 3.23 g of salt water. (05) Find : [ Atomic mass of K= 40 g, Cl = 35.5 g ] C1 g a) Formula unit mass of potassium chloride. b) Number of moles of potassium chloride dissolved in water. c) the number of potassium ions in 0.224 g of its hydroxide.
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a) 75.5 amu
b) 0.042 moles
c) 0.11 g
Explanation:
Given: Atomic mass of K= 40 g, Cl = 35.5 g, KCl = 3.23 g
a) Formula unit mass of potassium chloride:
We know that potassium chloride contains potassium and chlorine.
Hence KCl = 40 + 35.5 = 75.5 amu
b) Number of moles of potassium chloride dissolved in water:
Number of moles = mass/ molar mass
= 3.23 / 75.5
= 0.042 Moles
c) the number of potassium ions in 0.224 g of its hydroxide:
KOH → K⁺ + OH⁻
75.5 g of KOH contains 40 g of K⁺
∴ 0.224 g of KOH will contain x g of K⁺
∴ x = 40 × 0.224/ 75.5
= 0.11 g of Potassium ions
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