Question

PrepBuddy has an analog clock which consists of two hands one for hour and another for minute. She wants to calculate the shorter angle formed between hour and minute hand at any given time.

Answer 1

Answer:

analog clock which consists of two hands one for hour and another for minute. She wants to calculate the shorter angle formed between hour and minute hand at any given time.

Explanation:

testCases = int(input())

for i in range(testCases):

 h, m = map(int, input().split()

 h_pos = int( h * 30 + m * 0.5)

 m_pos = int( m * 6)

 if(h_pos - m_pos <= 180):

   angle = int(h_pos - m_pos)

 else:

   angle = int(m_pos - h_pos)

 if(angle < 0):

   angle *= -1  

 print(angle)

Answer 2

Answer:

#include<bits/stdc++.h>

using namespace std;

 

 int main()

 {   int t;

     cin>>t;

   for(int i=1;i<=t;i++){

   int h,m;

   cin>>h>>m;

   double h_angle=(60*h+1*m)/2;

   double m_angle=(h*0+m*6);

   double angle= abs(h_angle-m_angle);

   if(angle<=180){

     cout<<angle;

     cout<<endl;

   }

   else{

     cout<<(360-angle)<<endl;

   }

   }

   return 0;

 }

Explanation:

and also use while and for loop