Math, asked by VikrantVarshney, 1 day ago

Prese Present age of father is 48 years and that of his son is 16 years. Find the ratio of: (a) Present age of father to the present age of son. (b) Age of the father to the age of son, when son was 8 years old. (c) Age of father after 5 years to the age of son after 5 years. (d) Age of father to the age of son when father was 40 years old.​

Answers

Answered by smeet8077
0

Answer:

3

Step-by-step explanation:

48:16

48÷16=3

first of all we will write in ratio. form

then we will divide them

the answer of divide will be the ratio

Answered by AmyCrystal
0

Present age of father is 48 years and that of his son is 16 years.

Find the ratio of:

(a) Present age of father to the present age of son.

48 : 16

 =  \frac{48}{16}

 =  \frac{3}{1}

 = 3 : 1

(b) Age of the father to the age of son, when son was 8 years old.

Since, Since son age was 8 years, 8 years back

Father age 8 years back will be (48 - 8) 40 years.

40 : 8

 \frac{40}{8}

 \frac{5}{1}

5 : 1

(c) Age of father after 5 years to the age of son after 5 years.

Age of father after 5 years = 48 + 5 = 53 years

Age of son after 5 years = 18 + 5 = 21 years

53 : 21

(d) Age of father to the age of son when father was 40 years old.

40 : 8

 \frac{40}{8}

 \frac{5}{1}

5 : 1

Similar questions