Present age of a father is three years less than two times the square of his son’s age. Difference of their ages is 42 years, what are their present ages.
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Answer: son age=5 and father age =47
Step-by-step explanation:
F=2s^2-3
F-s=42
By solying them,
42+s=2s^2-3
S=5
Then put s in 1 equation
F=47
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