Question

Present age of a father is three years less than two times the square of his son’s age. Difference of their ages is 42 years, what are their present ages.

Answer 1

Answer: son age=5 and father age =47

Step-by-step explanation:

F=2s^2-3

F-s=42

By solying them,

42+s=2s^2-3

S=5

Then put s in 1 equation

F=47