Math, asked by pavanganesh168, 9 months ago

Present age of a father is three years less than two times the square of his son’s age. Difference of their ages is 42 years, what are their present ages.

Answers

Answered by Anonymous
1

Answer: son age=5 and father age =47

Step-by-step explanation:

F=2s^2-3

F-s=42

By solying them,

42+s=2s^2-3

S=5

Then put s in 1 equation

F=47

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