present age of a father is two more than 3 times the age of his son. 6 years ago, the product of their ages was 440 yrs. Assume the present age of the son be x and form a quadratic equation in x . hence find the present age of the father.
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Answer:x = (14 or -9)
Step-by-step explanation:
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Step-by-step explanation:
present age of father = 3x+2
six years ago '' = (3x+2)-6= 3x-4
" " age of son = x-6
given => (x-6)(3x-4)=440
=> 3x^2-22x+24=440
=> 3x^2-22x-416=0
x=16 or x= -26/3
age is positive ,so x =16
father age= 3*16+2
=50
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