Math, asked by cadeta6, 10 months ago

present age of A is 45 years 5 years ago the age of A was 5 times the age of son B how old is B now?

Answers

Answered by MissionRanaMagar
2

Step-by-step explanation:

Solution;

Here, present age of A is 45 years.

Let the present age of B be x years.

Now,

5 years ago, A was (45 - 5)years = 40 years

5 years ago, B was (x - 5) years

By question;

40 =5 (x - 5)

or, 40 = 5x - 25

or, 40 + 25 = 5x

or, 65 = 5x

or, 65/5 = x

or, x = 13

Hence, the present age of B is x years = 13 years.

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