Math, asked by asrayounuskhan11, 10 months ago

Present
age
of
Abhiram
is
7 times
of
the
his son's
product
age. 5 years later
of their ages
is
297.
Find
their
ages.​

Answers

Answered by bindidevi002
0

Step-by-step explanation:

NEWSMAKERS OF THE MONTH | 5-7. CURRENT ... This is the time to buckle up for IBPS CLERK and strike with ... peak rate of 28% on luxury and sin goods for five years to ... What will be the sum of their present ages?

Answered by GulabLachman
0

Present ages of Abraham and his son is 28 and 4 respectively.

Let the present age of Abraham be x.

It is given that the present age of Abraham is 7 tines that of his sons age.

Considering his son's present age to be y.

Then

x = 7y     ...(1)

After 5 years, Abraham becomes = (x+5) years and his son becomes = (y+5) years.

Now, the product of their ages is

= (x+5)(y+5)

This is equal to 297.

Replacing x as 7y from (1), we get,

(7y+5)(y+5) = 297

⇒ 7y² + 35y + 5y + 25 = 297

⇒  7y² + 40y - 272 = 0

⇒  7y² + 68y - 28y - 272 = 0

⇒  7y(y-4) +68(y-4) = 0

⇒  (7y+68)(y-4) = 0

From zero product rule, we get y = 4 as age cant be negative.

y = 4 years.

As x = 7y

So, x = 7(4) = 28 years.

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