Present
age
of
Abhiram
is
7 times
of
the
his son's
product
age. 5 years later
of their ages
is
297.
Find
their
ages.
Answers
Step-by-step explanation:
NEWSMAKERS OF THE MONTH | 5-7. CURRENT ... This is the time to buckle up for IBPS CLERK and strike with ... peak rate of 28% on luxury and sin goods for five years to ... What will be the sum of their present ages?
Present ages of Abraham and his son is 28 and 4 respectively.
Let the present age of Abraham be x.
It is given that the present age of Abraham is 7 tines that of his sons age.
Considering his son's present age to be y.
Then
x = 7y ...(1)
After 5 years, Abraham becomes = (x+5) years and his son becomes = (y+5) years.
Now, the product of their ages is
= (x+5)(y+5)
This is equal to 297.
Replacing x as 7y from (1), we get,
(7y+5)(y+5) = 297
⇒ 7y² + 35y + 5y + 25 = 297
⇒ 7y² + 40y - 272 = 0
⇒ 7y² + 68y - 28y - 272 = 0
⇒ 7y(y-4) +68(y-4) = 0
⇒ (7y+68)(y-4) = 0
From zero product rule, we get y = 4 as age cant be negative.
y = 4 years.
As x = 7y
So, x = 7(4) = 28 years.