Math, asked by MOHAMMADKHAN12, 1 month ago

Present age of AMAN is 2 more than 2 times of KHAN age.4 years before AMAN age was 8 times of KHAN age.find the present age of AMAN and KHAN

Answers

Answered by simarpreet171007
3

Let the present age of Amon’s son be x years.

Therefore, Aman’s age = 3x years.

According to question,

3x-10=5\left(x-10\right)3x−10=5(x−10)

\Rightarrow3x-10=5x-50⇒3x−10=5x−50

\Rightarrow3x-5x=-50+10⇒3x−5x=−50+10

\Rightarrow\ -2x=-40⇒ −2x=−40

\Rightarrow x=\frac{-40}{-2}=20⇒x=

−2

−40

=20 years

Hence, Aman’s son’s age = 20 years

And Aman’s age = 3 x 20 = 60 years.

PLEASE my answer as a brainliest ....

Answered by ajr111
9

Answer:

Present ages of :

  • AMAN = 12 years
  • KHAN = 5 years

Step-by-step explanation:

Given :

  • Present age of AMAN is 2 more than 2 times of KHAN age
  • 4 years before AMAN age was 8 times of KHAN age.

To find :

present age of AMAN and KHAN

Solution :

Let the present ages of AMAN be x and KHAN be y

  • According to first condition,

x = 2 + 2y

=> x - 2y = 2  ____[1]

  • According to second condition,

as this is 4 years before, we need to minus their ages by 4

(x-4) = 8(y-4)

=> x - 4 = 8y - 32

=> -x + 8y = 28 ____[2]

  • Adding eqn [1] and [2],

=> 6y = 30

=> y = 30/6 = 5

=> y = 5

Thus, present age of KHAN is 5 years

  • Now, Substituting y = 5 in equation [1],

x - 2(5) = 2

=> x - 10 = 2

=> x = 10 + 2

=> x = 12

Thus, present age of AMAN is 12 years

Hope it helps!!

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