Question

present age of bitu is 2 more than 2 times of sidhi age.4 years before bitu age was 8 times of sidhi age.find the present age of bitu and sidhi. WRITE EQUATION
THEN SOLVE

Answer 1

Step-by-step explanation:

⇝ Given :-

Present age of Bitu is 2 more than 2 times of Sidhi's age.

4 years ago Bitu's age was 8 times of Sidhi's age.

⇝ To Find :-

Their Present Ages

⇝ Solution :-

Let,

Sidhi's Present Age = \rm xx years

As Present age of Bitu is 2 more than 2 times of Sidhi's age.

Therefore,

Bitu's Present Age = = \rm (2x+2)(2x+2) years

❒ Four Years Ago ;

Sidhi's Age = \rm (x-4)(x−4) years

Bitu's Age = \rm (2x-2)(2x−2) years

⏩ According To Question :

\begin{gathered} \blue \bigstar \: \red{\text{Bitu's Age = 8(Sidhi's Age)}} \\ \end{gathered}

★Bitu’s Age = 8(Sidhi’s Age)

\begin{gathered}:\longmapsto \rm 2x - 2 = 8(x - 4) \\ \end{gathered}

:⟼2x−2=8(x−4)

\begin{gathered}:\longmapsto \rm 2x - 2 = 8x - 32 \\ \end{gathered}

:⟼2x−2=8x−32

\begin{gathered}:\longmapsto \rm 2x - 8x = - 32 + 2 \\ \end{gathered}

:⟼2x−8x=−32+2

\begin{gathered}:\longmapsto \rm \cancel- 6x = \cancel- 30 \\ \end{gathered}

:⟼

−

6x=

−

30

\begin{gathered}:\longmapsto \rm x = \cancel \frac{30}{6} \\ \end{gathered}

:⟼x=

6

30

\purple{ \large :\longmapsto \underline {\boxed{{\bf x = 5} }}}:⟼

x=5

Hence,

Sidhi's Present Age = \rm xx = 5 years

Bitu's Present Age = = \rm (2x+2)(2x+2) = 12 years

Therefore,

\begin{gathered}\pink{\begin{cases} \bf Sidhi's\:Present\:Age = 5 \:years \\ \\ \bf Bitu's\:Present\:Age = 12 \: years\end{cases}}\end{gathered}

⎩

⎪

⎪

⎨

⎪

⎪

⎧

Sidhi

′

sPresentAge=5years

Bitu

′

sPresentAge=12years

Answer 2

Answer:

Let present age of mother is x, then present age of his som =

5

2x

After 8 year

son's age

5

2x

+8

mother's age =x+8

And given that son's age is

2

1

time of mother's

5

2x

+8=

2

1

(x+8)

x=40

Hence ,present age of mother is 40