Question

Present age of bitu is 2 more than 2 times of sidhi age.4 years before bitu age was 8 times of sidhi age.find the present age of bitu and sidhi.

Answer 1

Answer:

Present age of Sidhi = 5 years

Present age of Bitu = 12 years

Step-by-step explanation:

Let,

• Present age of Sidhi = x
• Present age of Bitu = 2x + 2

4 years before,

• Age of Sidhi = x - 4
• Age of Bitu = 2x + 2 - 4 = 2x - 2

Also,

Bitu's age was 8 times of Sidhi's age

★ According to the Question :

⇒ 8 (x - 4) = 2x - 2

⇒ 8x - 32 = 2x - 2

⇒ 8x - 2x = - 2 + 32

⇒ 6x = 30

⇒ x = 30/6

⇒ x = 5

Present age of Sidhi = 5 years

• Present age of Bitu = 2x + 2

⇒ 2x + 2

⇒ 2 (5) + 2

⇒ 10 + 2

⇒ 12

Present age of Bitu = 12 years

Therefore, the present age of Bitu and Sidhi is 12 years and 5 years respectively.

Answer 2

Given :-

The Present age of Bitu is 2 more than 2 times of Sidhi age.4 years before Bitu age was 8 times of Sidhi age.

To Find :-

The Present age of Bitu and Sidhi.

Solution :-

Let the present age of Bitu = x and Sidhi = y

x = 2y + 2 (i)

4 years ago

Age of Bitu = (x - 4)

Age of Sidhi = (y - 4)

Bitu's age = 8(Sidhi's age)

(x - 4) = 8(y - 4) (ii)

Solving 2

x - 4 = 8y - 32

x - 8y = -32 + 4

x - 8y = -28 (iii)

Putting value of x from 1 in 3

2y + 2 - 8y = -28

-6y = -28 - 2

-6y = -30

6y = 30

y = 30/6

y = 5

Now

x = 2y + 2

x = 2(5) + 2

x = 12

Therefore

Age of Bitu = x = 12 years

Age of Sidhi = y = 5 years