Question

Present age of bitu is 2 more than 2 times of sidhi age.4 years before bitu age was 8 times of sidhi age.find the present age of bitu and sidhi.​

Answer 1

Answer:

The present ages of Bitu and Sidhi are 12 years and 5 years respectively.

Step-by-step-explanation:

Let the present age of Sidhi be x years.

From the first condition,

Present age of Bitu = ( 2x + 2 ) years

Now,

Age of Sidhi four years ago = ( x - 4 ) years

Age of Bitu four years ago = ( 2x + 2 - 4 ) = ( 2x - 2 ) years

From the second condition,

Age of Bitu four years ago = 8 ( x - 4 )

⇒ ( 2x - 2 ) = 8 ( x - 4 )

⇒ 2x - 2 = 8x - 32

⇒ - 2 + 32 = 8x - 2x

⇒ 6x = 30

⇒ x = 30 ÷ 6

⇒ x = 5

Now,

Present age of Sidhi = x = 5 years

Present age of Bitu = ( 2x + 2 ) = ( 2 * 5 + 2 )

⇒ Present age of Bitu = 12 years

∴ The present ages of Bitu and Sidhi are 12 years and 5 years respectively.

Answer 2

Present age of

Bitu = 12 years

Sidhi = 5 years

Step-by-step explanation:

QUESTION :-

Present age of Bitu is 2 more than 2 times of Sidhi age. 4 years before Bitu age was 8 times of Sidhi age. Find the present age of Bitu and Sidhi.

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SOLUTION :-

Let,

the present age of Sidhi as x

So,

4 years before age of Sidhi = x - 4

And,

Bitu's present age = 2x + 2

4 years before Bitu's age = 2x + 2 - 4

= 2x - 2

A.T.Q,

4 years ago,

Bitu's age = 8 × Sidhi's age

=> 2x - 2 = 8 × (x - 4)

=> 2x - 2 = 8x - 32

=> 2x - 8x = - 32 + 2

=> - 6x = - 30

=> x = (-30) ÷ (-6)

=> x = 5

Hence,

Present age of Sidhi = x = 5 years

And,

Present age of Bitu = 2x + 2

= 2(5) + 2

= 10 + 2

= 12 years

So,

The present ages of Bitu and Sidhi are 12 years and 5 years respectively.

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Hope it helps.

#BeBrainly :-)