Math, asked by yamunadevi7035, 9 months ago

Present age of father and son are in the ratio of 7:1 after 10 years it will be 2:1 find present age

Answers

Answered by akkirajuhema
1

Answer:

present age of father and son =7:1 (in ratio )

let the given ratio be, 7x and 1x

After 10 years their ages will be,

father's age:7x+10 years

son's age :1x+10 years

Now,

After 10 years ages will be in 2:1 ratio

= 2x, 1x

7x+10 = 2x

--------- ------ (cross multiplication)

1x+10 1x

7x+10*1x = 1x+10*2x

7x-2x =10-10

5x = 0

therefore X = 5

Now,

present age of father =7x =) 7*5 = 35 years

present age of son = 1x =) 1*5 = 5 years.

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