Math, asked by Anonymous, 4 months ago

Present age of father is 28 years
more than his son's age. Father's
age becomes 2 times of his son's
age after 20 years. Then what is
the present age of the father ?
1) 36 years
2)
38 years
3)
8 years
4)
28 years​

Answers

Answered by Anonymous
4

Answer:

Answer: Option A)

Steps:

Let the present age of son be 'x' years. Hence the present age of father according to the question is:

Age of father (present) = ( x + 28 ) years

Also, it is given that father's age would become 2 times of his son's age after 20 years.

⇒ Father's age + 20 years = 2 ( x + 20 )

Substituting Father's age from previous equation in the latest equation we get:

→ ( x + 28 + 20 ) = 2 ( x + 20 )

→ ( x + 48 ) = 2x + 40

→ 2x - x = 48 - 40

→ x = 8 years

Hence the present age of Son is 8 years.

Hence the present age of father is:

→ 8 + 28 = 36 years

Hence the present age of the father is 36 years.

Hence Option A) is the correct answer.

Answered by Anonymous
4

Answer:

Answer: Option A)

Steps:

Let the present age of son be 'x' years. Hence the present age of father according to the question is:

Age of father (present) = ( x + 28 ) years

Also, it is given that father's age would become 2 times of his son's age after 20 years.

⇒ Father's age + 20 years = 2 ( x + 20 )

Substituting Father's age from previous equation in the latest equation we get:

→ ( x + 28 + 20 ) = 2 ( x + 20 )

→ ( x + 48 ) = 2x + 40

→ 2x - x = 48 - 40

→ x = 8 years

Hence the present age of Son is 8 years.

Hence the present age of father is:

→ 8 + 28 = 36 years

Hence the present age of the father is 36 years.

Hence Option A) is the correct answer.

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