Question

present age of father is 45 years and that of his son is 15 years. find the ratio of: Age of the father to the age of the son when son was 12 years old​

Answer 1

Step-by-step explanation:

⭐ Given

⬛ Present age of Father's is 45 years.

⬛ Present age of Son's is 15 years.

⬛ When son's age was 12 years then Father's age was 42.

⭐ To Find

⬛ The ratio of - Age of the father to the age of son.

$\Large\rm\bigstar{\underline{Required\:Solution:}}$

Let Father's age is F and Son's

Let Father's age is F and Son's age is S.

Then Ratio will be,

$\boxed{Ratio=\bf\dfrac{F}{S}=\bf\:F:S}$

Ratio of - Father's age and son's

age is :-

$Ratio = \bf \cancel\dfrac{42}{12}^{ \bf\dfrac{7}{2} } \\ \\ \implies \bf \: 7:2\:\:\:\:\:\:\:\:\:$

Hence ratio of Father's age and son's age is 7:2.

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Answer 2

Answer:

• The ratio of age of the father to the age of the son when son was 12 years old is 7:2.

Given:

• Present age of father is 45 years.
• Present age of his son is 15 years.

To find:

• Find the ratio of: Age of the father to the age of the son when son was 12 years old?

As we know that,

Age of the father to the age of the son when son was 12 years old is 42 years ( 15 - 12 = 3 years. So, 45 years - 42 years. )

Solution:

Let us assume father's age as F

And, Let us assume son's age as S

We know that, Age of the father to the age of the son when son was 12 years old is 42 years.

Ratio will be :

$\boxed{ \bf Ratio = \bf { \dfrac{42}{12} }}$

By cancelling, We get :

$\leadsto \bf { \cancel{\dfrac{42}{12}} } = \dfrac{7}{2}$

⇒Ratio = 7 : 2

Hence, The ratio of age of the father to the age of the son when son was 12 years old is 7:2.