Math, asked by Sveta, 10 months ago

present age of father is 6 times that of his son.After 12 years father's age will be 3 times that of his son.find the present age of his son

Answers

Answered by help1559
42

Answer:

8 years

hope it will help you

Attachments:
Answered by Sauron
50

\mathfrak{\large{\underline{\underline{Answer: }}}}

Son is 8 years old and father is 48 years old.

\mathfrak{\large{\underline{\underline{Step-by-step \:explanation:}}}}

\textsf{\underline{\underline{Given :}}}

Present age of father = 6 times that of his son

After 12 years = father's age will be 3 times of his son

\textsf{\underline{\underline{To find :}}}

Son's present age

\textsf{\underline{\underline{Solution : }}}

\textbf{\small{\underline{Let the present ages be - }}}

  • Son as x
  • Father as 6x

\textbf{\small{\underline{Ages after 12 years - }}}

  • Son = (x + 12)
  • Father = (6x + 12)

\rule{300}{1.5}

\textbf{\small{\underline{According to the Question - }}}

After 12 years = father's age will be 3 times of his son

\rm{\implies} \: (6x + 12) = 3(x + 12) \\ \rm{\implies} \: 6x + 12 = 3x + 36 \\ \rm{\implies} \: 6x - 3x = 36 - 12 \\ \rm{\implies} \: 3x = 24 \\ \rm{\implies} \: x =  \frac{24}{3} \\ \rm{\implies} \: x = 8

Son's age = 8 years old

\rule{300}{1.5}

Value of 6x

\rm{\implies} \: 6(8) \\ \rm{\implies} \: 48

Father is 48 years old.

\therefore Son is 8 years old and father is 48 years old.

\rule{300}{1.5}

\mathfrak{\large{\underline{\underline{Verification :}}}}

Ages after 12 years -

  • Son = 8 + 12 = 20
  • Father = 48 + 12 = 60

Father turns thrice the age of his son after 12 years, hence the answer is correct.

\therefore Son is 8 years old and father is 48 years old.

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