present age of father is eaual to twice the sum of ages of his 2 children.22 years hence the sum of the ages of his children will be same as his age then find present age of father
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Let the age of 2 children is x
And father's age is Y
Y=2X....(1)
After 22 years
X + 44 = Y + 22
X - Y = - 22
Now put Y= 2X
X - 2X = -22
-X = -22
X = 22
Then Y = 2 * 22= 44
Hence age of father will be 44 years
And father's age is Y
Y=2X....(1)
After 22 years
X + 44 = Y + 22
X - Y = - 22
Now put Y= 2X
X - 2X = -22
-X = -22
X = 22
Then Y = 2 * 22= 44
Hence age of father will be 44 years
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let the fathers age be =x
fathers present age =2x22=44
fathers present age =2x22=44
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