Present age of father is3times the present age of son. 5years ago sum of their ages were 50. Find the present ages
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Answered by
0
Let present ages be F and S
F = 3S
F-5 + S-5 = 3S-5+ S-5 = 4S - 10 = 50
Therefore S = 60/4 = 15
F = 3S = 45
Answered by
12
Answer:
Given:
Present age of father is3 times the present age of son. 5years ago the sum of their ages was 50.
To Find:
We need to find the present age of son and father.
Solution:
Let Present age of son = x
and Present age of father = 3x
5 years ago,
Age of son = x - 5
Age of father = 3x - 5
According to the question,
x - 5 + 3x - 5 = 50
4x - 10 = 50
4x = 50 + 10
4x = 60
x = 60/4
x = 15
Therefore present age of son = x years which is 15 years and age of father = 3x which is 3 × 15 = 45 years.
Hence, present age of son is 15 years and present age of father is 45 years.
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