Math, asked by alka97, 5 hours ago

present age of Mohit and Mayank are in the ratio 11:8 . after 8 years the ratio of there ages will be 5:4 find there present age.

Answers

Answered by takshiljain007

Answer:

Let the Present age of Mohit be 11x and the age of Mayank be 8x. After 8 years, the ratio of their ages will be . The present ages of Mohit and Mayank are, 11 x = 11 ( 2 ) = 22 , 8 x = 8 ( 2 ) = 16 . Therefore, the present ages of Mohit and Mayank are 22 and 16 respectively.

Step-by-step explanation:

please mark as brilliantist answer

Answered by dixitajatwa3

Answer:

11x+8=. 5x

____. __. solve this you will get the answer

8x +8. 4x

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present age of Mohit and Mayank are in the ratio 11:8 . after 8 years the ratio of there ages will be 5:4 find there present age.​

Answers

present age of Mohit and Mayank are in the ratio 11:8 . after 8 years the ratio of there ages will be 5:4 find there present age.