Question

present age of rams mother is 4 times than the age of ram. 5 years ago the sum of their ages was 30 find their present ages​

Answer 1

$\sf{\underline{\underline{Question :-}}}$

present age of rams mother is 4 times than the age of ram. 5 years ago the sum of their ages was 30 find their present ages.

$\sf{\underline{\underline{Solution :-}}}$

Let,

• Ram age = x
• Ram's mother's age = y

• The age of ram's mother is 4 times the age of ram y = 4x

† Five years ago,

• the sum of their ages was 30 years:-

$\sf→ y - 5 + x - 5 = 30$

$\sf→ 4x - 5 + x - 5 = 30$

$\sf→ 5x - 10 = 30$

$\sf→ 5x = 30 + 10$

$\sf→ 5x = 40$

$\sf→ x = 40/5 = 8$

$→\sf y = 4x = 4×8= 32$

so, at the present,

• Ram is 8 years old
• Ram's mother is 32 years old

Answer 2

GIVEN:-

• Present age of Ram = x

• Present age of Ram's mother = 4x

TO FIND-:

• Their Present ages.

Now,

According to Question,

5 Years ago,

$\implies\rm\red{Ram's\:ge = x-5}$

$\implies\rm\blue{Ram's\:mother\:age= 4x-5}$

• The sum of their ages was 30.

Therefore,

$\implies\rm{(x-5)+(4x-5)=30}$

$\implies\rm{x-5+4x-5=30}$

$\implies\rm{5x-10=30}$

$\implies\rm{5x=40}$

$\implies\rm{x=\dfrac{\cancel{40}}{\cancel{5}}}$

$\implies\rm{x= 8}$.

Hence,

$\implies\sf{Present\:age\:of\:Ram = x= 8}$

$\implies\sf{Present\:age\:of\:Ram's\:mother=4x = 32}$

Their Present ages are 8 and 32 Respectively.

VERIFICATION

• The sum of their ages 5 years ago was 30.

$\implies\rm{(7-5)+(32-5)=30}$

$\implies\rm{2+28=30}$

$\implies\rm{30=30}$

Hence, Verified ✔️